48x^2-26x-35=0

Solution for 48x^2-26x-35=0 equation:

48x^2-26x-35=0

a = 48; b = -26; c = -35;
Δ = b2-4ac
Δ = -262-4·48·(-35)
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7396}=86$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-86}{2*48}=\frac{-60}{96}
=-5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+86}{2*48}=\frac{112}{96}
=1+1/6
$